Hi

Note: the vertex form of a parabola,  where(h,k) is the vertex

f(x)=x^2-4x+3 Or f(x)= (x-2)^2 -1 in vertex form: x-intercepts (3,0)&(1,0)

vertex Pt(2,-1), axis of symmetry x = 2, (0,3) the y-intercept



f(x) = (x+1)^2-4  x-intercepts (1,0)&(-3,0)

vertex Pt(-1,-4), axis of symmetry x = -1, (0,-3) the y-intercept



 

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