Hi,

solving 

c^2+3c-54=0 

factoring

(c+9)(c-6)=0 Note:SUM of the inner product(9c) and the outer product(-6c) = 3c

(c+9)=0

c = -9

(c-6)=0

c = 6 

RELATED QUESTIONS

c+(4-3c)-2=0 (answered by stanbon)

3c-5d=c+2 solve for... (answered by rfer)

3c^2=10c solve for C... (answered by jim_thompson5910)

3c^2-(3c)^2=

A. -3c^2
B. -6c^2
C. 0
D. c
E.... (answered by Fombitz)

Solve, unless there is no solution?

c^2 + 3c - 28 = 0

Thank... (answered by solver91311)

How can I solve this problem?
4c+3(2+c)=4c+6+3c
         =4c+3c+6
 (answered by AnlytcPhil)

how do solve this problem... (answered by mananth)

please help me solve this equation

{{{3c-2d=2}}}... (answered by Alan3354)

-8<-2-3c<8  Solve
-8+2< -2-3c+2<8+2
-6<-3c < 10
-2< -c < 3.333
2 > c > -3.333
 (answered by ki)