First, we need to understand that synthetic division works for divisors of the form: (x - a) where "s" is some number. So we need to change (x+2) to be a subtraction: (x - (-2)).
Also it is important to represent every power of the variable when using synthetic division. So we will need a zero coefficient for the missing squared term. Putting these together we get:
-2 | 5 0 6 8
-10 20 -52
----------------
5 -10 26 -44
The number in the lower right corner is the remainder. As you may recall the remainder is put into the numerator of a fraction with the divisor in the denominator.
The rest of that bottom line is the rest of the quotient. So: