# SOLUTION: The real zeros (arranged in increasing order ) of the polynomial P(x)=x^4-3x^3-11x^2+25x+12 are given by x1_________ x2___________ x3____________ x4____________

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: The real zeros (arranged in increasing order ) of the polynomial P(x)=x^4-3x^3-11x^2+25x+12 are given by x1_________ x2___________ x3____________ x4____________      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 370224: The real zeros (arranged in increasing order ) of the polynomial P(x)=x^4-3x^3-11x^2+25x+12 are given by x1_________ x2___________ x3____________ x4____________Answer by stanbon(57424)   (Show Source): You can put this solution on YOUR website!The real zeros (arranged in increasing order ) of the polynomial P(x)=x^4-3x^3-11x^2+25x+12 are given by ---- I graphed it and found solid zeroes at x = -3 and at x = 4. Using those and synthetic division solve the resulting quadratic quotient: -3)....1....-3....-11....25....12 ........1.....-6....7.....4....|..0 ========================================= 4)....1....-6....7....4 .......1.....-2...-1...|..0 ---- Quotient: x^2-2x-1 Quadratic Formula: x = [2+-sqrt(4-4*-1)]/2 x = [2+-2sqrt(2)]/2 ------ x1 = -3______ x2 = 1-sqrt(2)_______ x3 = 1+sqrt(2)_______ x4 = 4____________ ============================================================================= Cheers, Stan H.