SOLUTION: factor completely: y^4-1
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Question 369350: factor completely: y^4-1
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
y^4-1
=(y^2+1)(y^2-1)
=(y^2+1)(y+1)(y-1)
...
m.ananth@hotmail.ca
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