SOLUTION: 108y^9 + 4y^3
Algebra.Com
Question 367984: 108y^9 + 4y^3
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
I assume that you would like to factor.
Divide both terms by 4y^3 to factor.
108y^9 divided by 4y^3 = 27y^6.
4y^3 divided by 4y^3 = 1.
Final Answer: 4y^3(27y^6 + 1).
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