SOLUTION: Hello, I have been working on this problem for over two hours...any help would be most sincerely appreciated. (xy), over 2/y-1/x I have been using (xy) as the LCD.

Question 367360: Hello,
I have been working on this problem for over two hours...any help would be most sincerely appreciated.

(xy), over 2/y-1/x
I have been using (xy) as the LCD.
I have multiplied (xy) over one, by the (xy) numerator and I then distribute the (xy) to the 2/y-1/x denominator and I get 2xy+x^2+y^2, over 2x-y
I keep coming up with "4" as an answer. The book has 2x+y
Many thanks for your help
Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(xy), over 2/y-1/x
I have been using (xy) as the LCD.
I have multiplied (xy) over one, by the (xy) numerator and I then distribute the (xy) to the 2/y-1/x denominator and I get 2xy+x^2+y^2, over 2x-y
I keep coming up with "4" as an answer. The book has 2x+y
-------------------------
I cannot get an answer of 2x+y out of the problem you
have posted.
--------------------
Cheers,
Stan H.

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Use parentheses and spaces so someone might figure out what the problem is.
No verbal descriptions, please.
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