SOLUTION: I'm having some trouble with factoring Polynomials with a coefficient in front of the squared variable. 10r2-25r-6. I've tried (2r+2)(5r-3).
Algebra.Com
Question 366639: I'm having some trouble with factoring Polynomials with a coefficient in front of the squared variable. 10r2-25r-6. I've tried (2r+2)(5r-3).
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Looking at we can see that the first term is and the last term is where the coefficients are 10 and -6 respectively.
Now multiply the first coefficient 10 and the last coefficient -6 to get -60. Now what two numbers multiply to -60 and add to the middle coefficient -25? Let's list all of the factors of -60:
Factors of -60:
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -60
(1)*(-60)
(2)*(-30)
(3)*(-20)
(4)*(-15)
(5)*(-12)
(6)*(-10)
(-1)*(60)
(-2)*(30)
(-3)*(20)
(-4)*(15)
(-5)*(12)
(-6)*(10)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -25? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -25
First Number | Second Number | Sum | 1 | -60 | 1+(-60)=-59 |
2 | -30 | 2+(-30)=-28 |
3 | -20 | 3+(-20)=-17 |
4 | -15 | 4+(-15)=-11 |
5 | -12 | 5+(-12)=-7 |
6 | -10 | 6+(-10)=-4 |
-1 | 60 | -1+60=59 |
-2 | 30 | -2+30=28 |
-3 | 20 | -3+20=17 |
-4 | 15 | -4+15=11 |
-5 | 12 | -5+12=7 |
-6 | 10 | -6+10=4 |
None of these pairs of factors add to -25. So the expression cannot be factored
RELATED QUESTIONS
I'm having a problem in figuring out what the "2" in front of 2x(squared) means.
This is (answered by jim_thompson5910)
I am having some trouble with factoring by grouping. {{{a^2b+3a^2+2b+6}}}.Help please?... (answered by drglass)
I am having trouble factoring completely with polynomials:... (answered by Alan3354)
Hi,
There's a word problem on vectors that I've been having trouble with: "What... (answered by htmentor)
Hi, I'm having trouble factoring polynomials including quadratics. I found an answer for... (answered by stanbon)
I am having trouble with equations in fractions with a variable, can you help?... (answered by rfer)
Im having trouble factoring polynomials:
please show the steps and explain (simply)... (answered by lwsshak3)
How do i simplify this with a coefficient in front of the parentheses without a... (answered by josgarithmetic)
The degree three polynomial f(x) with real coefficients and leading coefficient 1, has 4... (answered by AnlytcPhil)