SOLUTION: Can you help me with dividing polynomials? Here's the equation: 2x^3 - 3x^2 + 4x

SOLUTION: Can you help me with dividing polynomials? Here's the equation: 2x^3 - 3x^2 + 4x - 21 / 2x + 1

Question 366: Can you help me with dividing polynomials? Here's the equation:
2x^3 - 3x^2 + 4x - 21 / 2x + 1
Answer by ashipm01(26) (Show Source): You can put this solution on YOUR website!

First you would take the 2x and see how many times that will go into 2x^3. Since it goes into 2x^3 x^2 times you multiply the 1 by x^2.

Now you should have (-4x^2+4X-21) as your divisor since you subtract the x^2 from the -3x^2 and you subtract the 2x^3 from the 2x^3.

Your current answer is x^2 after the first step.

Now you do the same process. You take the 2x and see how many times it will divide into -4x^2 which is -2x times. So now you multiply the 1 by 2x.

You then add the 4x^2 that you got when you multiply -2x *2x (you add it because you invert the sign so you can cancel the terms out) to -4x^2 which yields 0. You then multiply 1 * -2x and switch it from negative to positive and add that to the 4x to get 6x.

Your current answer should now be x^2 - 2x after the second step.

Next you take and see how many times 2x will go into 6x which is 3 times. Now you multiply 1 * 3 and invert the sign to get -3. Then you cancel out the 6x and you subtract 3 from -21 to get -24.

Your current answer now should be x^2 - 2x +3 after the third step.

Finally you add the remainder which is -24 and divide it by the divisor (2x+1) to get a final answer of:

I hope this helps,
Alex
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