SOLUTION: Good evening! I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t I tried factoring: = t(t^4 - 6t^2 + 9) = t(t^2 -3)^2 t = 0 (t^2

SOLUTION: Good evening! I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t I tried factoring: = t(t^4 - 6t^2 + 9) = t(t^2 -3)^2 t = 0 (t^2 - 3)^2 = 0 sqrt of bot

Question 362913: Good evening!
I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t
I tried factoring:
= t(t^4 - 6t^2 + 9)
= t(t^2 -3)^2
t = 0
(t^2 - 3)^2 = 0
sqrt of both sides (can i do that?)
t^2 - 3 = 0
t = +/- sqrt(3)
This definitely doesn't look right but I'm not sure how else to solve this. Any help you can provide is great appreciated! Thanks for your time :)
Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!

You did just fine:

The zeros are 0 and 

The graph is 



You can see it has double zeros at , about �1.7,
and a single zero at 0.

Edwin

RELATED QUESTIONS
{{{ (t^2-1)/(t^2-4) }}} + {{{ (9t+9)/(4t+12) }}} * {{{ (2-t)/(t^2+2t-3) }}} The back... (answered by Alan3354,greenestamps,MathTherapy)

t^3-6t/t^2-49 (answered by stanbon)

6t=3(t+4)t (answered by stanbon)

Solve t^2 + 3 =... (answered by unlockmath,solver91311)

t^2-6t-27 (answered by algebrahouse.com)

t(5t^2+6t) (answered by rfer)

Divide and simplify for t^2+6t/t^2+3t-18 divided by... (answered by edjones)