SOLUTION: How do you factor 1/2x^2+x-14/3=0?

Question 357414: How do you factor 1/2x^2+x-14/3=0?
Found 2 solutions by ewatrrr, edjones:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
Note: first lets clear the denominators
1/2x^2+x-14/3=0
Multiplying thru by 6
3x^2 + 6x -28 = 0
factoring using the quadradic formula

Calcutor makes short work of finding x
x = 2.215
x = -4.215

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
1/2x^2+x-14/3=0
3x^2+6x-28=0 multiply each side by 6.
x=-1-(sqrt(93)/3), x=-1+(sqrt(93)/3) see below.
.
Ed
.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=372 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.21455025366432, -4.21455025366432. Here's your graph:

RELATED QUESTIONS
How do you factor:... (answered by MathLover1)
How do you factor... (answered by MathLover1)
how do you factor:... (answered by richwmiller)
How do you factor... (answered by richwmiller)
How do you factor {{{ x^3/2 - x^1/2... (answered by oberobic,josmiceli,stanbon)
how do you factor (2x+3)^2 - (2x... (answered by solver91311)
how do you factor... (answered by Mathematicians,richwmiller)
How do you factor this... (answered by MathLover1)
how do you factor this... (answered by Zoop)