SOLUTION: Hi, I need to know how to set this problem up correctly: the answer is x^8 y16 with 3 under it the problem is 12x^7 y9 with 36xy^7 under it this is what I did to rewrite it

Question 356535: Hi, I need to know how to set this problem up correctly: the answer is
x^8 y16 with 3 under it
the problem is 12x^7 y9 with 36xy^7 under it
this is what I did to rewrite it in an equivalent form with positive exponents
12^7 x^7 y^9 and 36xy^7 under
12x^1 y^9=x8
x^7 y^9=16y
12 divide by 36xy =3
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(12x^7y^9)/36xy^7
12/36=1/3
x^7/x=x^6
y^9/y^7=y^2
SO
x^6y^2/3 Answer.
Check for negative exponents.
.
Ed
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