SOLUTION: how do you work this problem (m^2-1)/(m-1)^2*(2m-2)/(3m+3)
Algebra.Com
Question 351955: how do you work this problem (m^2-1)/(m-1)^2*(2m-2)/(3m+3)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Look for common factors.
RELATED QUESTIONS
m-(2m-3)=1-3m-2 (answered by tommyt3rd)
m = (1/3)(xy)^2
I'm solving for x
m = 1/3(x^2^y2)
m = x^2y^2/3
3m = x^2y^2
(answered by Edwin McCravy)
I need help solving this problem in it lowest term
(m^2-1)/((m-1) ) ∙... (answered by robertb)
how do I solve this rational expression?
m^2+2m-24
_________
m^2-3m
(answered by rothauserc)
3m-2(m-3)=1 (answered by rfer)
how can i do this problem 4m-2(3m+2)-4(m-1)
(answered by stanbon)
44. m^3+2m^2-3m=0
(answered by stanbon,hayek)
m^3+2m^2-3m=0 (answered by jim_thompson5910)
How do you solve this equation:... (answered by josmiceli,unlockmath)