SOLUTION: (2x^2-9x+4)/(6x^2+7x-5)

Question 349099: (2x^2-9x+4)/(6x^2+7x-5)
Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(2x^2-9x+4)/(6x^2+7x-5)
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Factor:
2x^2-9x+4
= 2x^2-8x-x+4
=2x(x-4)-(x-4)
= (x-4)(2x-1)
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6x^2+7x-5
= 6x^2+10x-3x-5
= 2x(3x+5)-(3x+5)
= (3x+5)(2x-1)
====================
Factored form of your problem:
[(x-4)(2x-1)]/[(3x+5)(2x-1)]
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= (x-4)/(3x+5)
=====================
Cheers,
Stan H.
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Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(2x^2-9x+4)/(6x^2+7x-5)
...
(2x^2-8x-x+4) / (6x^2+10x-3x -5)
..
2x(x-4)-1(x-4)/2x(3x+5)-1(3x+5)
...
(2x-1)(x-4)/(2x-1)(3x+5)
...
(x-4)/(3x+5)
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