SOLUTION: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10-4 Thank you s much for all of your help!!!!

Question 346076: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10-4
Thank you s much for all of your help!!!!
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
I assume you mean
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From the graph, there is one positive real zero, which means the remaining two roots are imaginary.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4
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# of sign changes in g(x) is 3 ; so 3 or 1 positive Real zeros.
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# of sign changes in g(-x) is 0 ; so no negative Real zeros.
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Fact: There is one positive around x = 0.4606
There are no negative so there are 2 imaginary.
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Cheers,
Stan H.
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