Question 34474: I mistyped before!! I can't get them to line up..?
(x-y) + (x+y) - (2x)
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(x^2-y^2) (x^2-y^2) (y^2-x^2) Answer by mukhopadhyay(490) (Show Source):
You can put this solution on YOUR website! (x-y)/(x^2-y^2) + (x+y)/(x^2-y^2) - 2x/(y^2-x^2)
= (x-y)/(x^2-y^2) + (x+y)/(x^2-y^2) - 2x/(-1)(x^2-y^2)
= (x-y)/(x^2-y^2) + (x+y)/(x^2-y^2) + 2x/(x^2-y^2)
= [1/(x^2-y^2)][(x-y)+(x+y)+2x] = [1/(x^2-y^2)][4x]
= 4x/(x^2-y^2)