SOLUTION: Find values of c so that the equation will have two solutions, one solution, and no real solution.
x^2+4x+c=0
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Question 34261This question is from textbook McDougal Littell Algebra1
: Find values of c so that the equation will have two solutions, one solution, and no real solution.
x^2+4x+c=0
This question is from textbook McDougal Littell Algebra1
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
To find values of c you need values for x, but we can simplify:
x^2+4x+c=0
(x^2+4x)=-c
(x + 2)^2 = 4 - c
4 - (x + 2)^2 = c
The answer for c depends on the value for x. With the information you provided, we can assume that any number can be used for x.... so infinitely many.
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