SOLUTION: a=b
ab=b2
ab-a2 = b2-a2
a(b-a)=(b+a)(b-a)
a=b+a
a=a+a
a=2a
1=2
My teacher says that 1=2 but this problem is NOT correct, can you explain to my why it will not work?
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: a=b
ab=b2
ab-a2 = b2-a2
a(b-a)=(b+a)(b-a)
a=b+a
a=a+a
a=2a
1=2
My teacher says that 1=2 but this problem is NOT correct, can you explain to my why it will not work?
Log On
Question 342530: a=b
ab=b2
ab-a2 = b2-a2
a(b-a)=(b+a)(b-a)
a=b+a
a=a+a
a=2a
1=2
My teacher says that 1=2 but this problem is NOT correct, can you explain to my why it will not work? Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Since you're assuming that a=b, this means that . So when you divide both sides by , you're basically dividing by zero (which is NOT allowed).
(