SOLUTION: a rectangular aea is to enclosed by a fence then divided down the middle by another piece of fence then divided by another piece of fence .if 3600 metres of fence is available ,fin
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Question 332439: a rectangular aea is to enclosed by a fence then divided down the middle by another piece of fence then divided by another piece of fence .if 3600 metres of fence is available ,find the maximum area that can be enclosed
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a rectangular area is to enclosed by a fence then divided down the middle by
another piece of fence then divided by another piece of fence .
if 3600 metres of fence is available, find the maximum area that can be enclosed
:
From the description I see something like this
______
|_|_|_|; 3 enclosed areas
:
2L + 4W = 3600
Simplify, divide by 2
L + 2W = 1800
L = (1800-2W)
:
A = L*W
Replace L with (1800-2W)
A = W(1800-2W)
A quadratic equation
A = -2W^2 + 1800W
Max area occurs at axis of symmetry which is
W =
W =
W = 450 m, width for max area
:
Find L
L = 1800-2(450)
L = 900 m, length for max area
:
Find max area
900 * 450 = 405,000 sq/m is max area
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