SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. f(x)=1/3(x+1)^2+4

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Question 331562: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. f(x)=1/3(x+1)^2+4

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
1/3(x+1)^2+4
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The line of symmetry is x = -1
f(-1) = 4 --> vertex at (-1,4)
+4 is the minimum value of f(x)
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http://www.padowan.dk.com

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