SOLUTION: x^2/(3x^2-11x+6) - 4/(x-3) = -2/(3x-2) I get x^2 - 4(3x-2) = -2(x-3) x^2 - 12x + 8 + -2x+6 x^2

SOLUTION: x^2/(3x^2-11x+6) - 4/(x-3) = -2/(3x-2) I get x^2 - 4(3x-2) = -2(x-3) x^2 - 12x + 8 + -2x+6 x^2 - 10x +2 ?????? where did i go wrong?

Question 325471: x^2/(3x^2-11x+6) - 4/(x-3) = -2/(3x-2)
I get
x^2 - 4(3x-2) = -2(x-3)
x^2 - 12x + 8 + -2x+6
x^2 - 10x +2
?????? where did i go wrong?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You're off to a great start. You just need to solve now.

Start with the given equation.

Notice that the quadratic is in the form of where , , and

Let's use the quadratic formula to solve for "x":

Start with the quadratic formula

Plug in , , and

Negate to get .

Square to get .

Multiply to get

Subtract from to get

Multiply and to get .

Simplify the square root (note: If you need help with simplifying square roots, check out this solver)

Break up the fraction.

Reduce.

or Break up the expression.

So the solutions are or

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