Question 32447This question is from textbook Algebra 2
: I have to factor this polynomial, I know it has to be grouped, but I cant reach the solution provided by the text.
x^2+2xy+2x+y^2+2y-8 This question is from textbook Algebra 2
You can put this solution on YOUR website! x^2 + 2xy + 2x + y^2 + 2y - 8
there are different ways through which you can factorise the equation...I am here factorising upto least level/...
here we edit this problem and we get
=(x^2 + y^2 + 2xy) + (2x + 2y) - 8
Now see carefully, you find that in first three variables in brackets you can apply the following formula.
(a+b)^2 = (a)^2 + (b)^2 + 2(a)(b).....
here a = x and b = y ...
on applying the formula we get..
= (x+y)^2 + (2x + 2y) - 8
now take 2 commom from (2x + 2y) and we get
= (x+y)^2 + 2(x + y) - 8
Now take (x+y)common from (x+y)^2 + 2(x + y) and we get....
= (x+y) [(x+y) - 2 ] - 8
on solving brackets we get...
= (x+y) [x+y - 2 ] - 8
= (x+y) x + y - 2 - 8
= (x+y) (x + y - 6)
Hope this will help you
Please feel free to revert back for any further queries
