SOLUTION: Unsure of how to type "X to the third" etc so it appears as X3
7-X..........X3+27
___....x....________
X+3.........X2-9X+14
7X3+189-X4-27X.......6X3+147
___________ __
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Question 32327: Unsure of how to type "X to the third" etc so it appears as X3
7-X..........X3+27
___....x....________
X+3.........X2-9X+14
7X3+189-X4-27X.......6X3+147
______________ = ____________ Is This Correct? Thank You Very Much!
X3+4X2-13X+42......X4+4X2+14X
(That reads as 6X to the third plus 147 over
X to the 4th + 4X squared + 14X)
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
[(7-x)/(x+3)][(x^3+27)/(x^2-9x+14)]
=[(7-x)/(x+3)][(x+3)(x^2-3x+9)/(x-7)(x-2)]
=[-(x-7)/(x+3)][(x+3)(x^2-3x+9)/(x-7)(x-2)]
= -(x^2-3x+9)/(x-2)
Answer: -(x^2-3x+9)/(x-2)
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