SOLUTION: The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16t square feet, where t is the time in seconds. According to
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-> SOLUTION: The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16t square feet, where t is the time in seconds. According to
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Question 32232: The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16t square feet, where t is the time in seconds. According to the model, how high is the ball after 7 seconds. I tried puttung 7 in the place of t and came up with a negative number. Answer by stanbon(48569) (Show Source):
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