# SOLUTION: given: P(x)=x^4-x^3-5x^2-x+6 Find all real and non- real zeroes of P(x). Thanks for taking the time to look at this problem, the concept of this type of problem is a bit co

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: given: P(x)=x^4-x^3-5x^2-x+6 Find all real and non- real zeroes of P(x). Thanks for taking the time to look at this problem, the concept of this type of problem is a bit co      Log On

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 Question 319714: given: P(x)=x^4-x^3-5x^2-x+6 Find all real and non- real zeroes of P(x). Thanks for taking the time to look at this problem, the concept of this type of problem is a bit confusing to me at the moment and I am not really sure if I am working them right. Appreciate any input that can be given.Answer by stanbon(57361)   (Show Source): You can put this solution on YOUR website! given: P(x)=x^4-x^3-5x^2-x+6 Find all real and non- real zeroes of P(x). ---- Note: Since the coefficients add up to zero, x = 1 is a zero. --- Use synthetic division to find other zeroes: --- 1)....1....-1....-5....-1....6 .......1.....0.....-5....-6...|..0 ===================================== Quotient: x^3 -5x -6 --- This quotient has a zero around x = 2.6891, but that is the only Real zero my calculator will pick up. ---- It appears there are two complex zeroes, but I cannot pin them down. ----- Cheers, Stan H.