SOLUTION: What is the vertex of f(x)=-x^2+2x+4?

Question 319410: What is the vertex of f(x)=-x^2+2x+4?

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
f(x)=-x^2+2x+4
.
The x-coordinate is the "axis of symmetry":
x = -b/(2a) = -2/(-2) = 1
.
To find the y-coordinate, plug it in:
f(1) = -1^2+2(1)+4
f(1) = -1+2+4
f(1) = 5
.
vertex the is at (1,5)

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