SOLUTION: FInd three consecutive numbers where the product of the smaller two numbers is 28 less than the suare of the largest number?

Question 319114: FInd three consecutive numbers where the product of the smaller two numbers is 28 less than the suare of the largest number?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x, x+1 & x+2 be the 3 consecutive numbers.
x(x+1)=(x+2)^2-28
x^2+x=x^2+4x+4-28
x^2-x^2+x-4x=-24
-3x=-24
x=-24/-3
x=8 ans. for the smallest number.
Proof:
8+1=9 ans. for the middle number.
8+2=10 ans. for the largest number.
Proof:
8*9=10^2-28
72=100-28
72=72
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