SOLUTION: Will someone please help me solve thes problems?
1) 36y^5-39y^4-12y^3
2) Factor completely
4x^3-10x^2-24x
Algebra.Com
Question 318963: Will someone please help me solve thes problems?
1) 36y^5-39y^4-12y^3
2) Factor completely
4x^3-10x^2-24x
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1) 36y^5-39y^4-12y^3
common factor: 3y^3
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= (3y^3)(12y^2 - 13y - 4)
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= (3y^3)(12y^2 - 16y + 3y -4)
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= (3y^3)(4y(3y-4)+(3y-4))
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= (3y^3)(3y-4)(4y+1)
==============================
2) Factor completely
4x^3-10x^2-24x
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= 2x(2x^2 - 5x - 12)
----
= 2x(2x^2-8x+3x-12)
---
= 2x(2x(x-4)+3(x-4))
---
= 2x(x-4)(2x+3)
======================
Cheers,
Stan H.
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