SOLUTION: jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together?
Algebra.Com
Question 315624: jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
in some time (t), Jack will mow t/3 of the lawn
___ during the same time, Marilyn will mow t/7 of the lawn
___ these two fractions add up to the whole lawn
(t/3) + (t/7) = 1
multiplying by 21 (LCD) ___ 7t + 3t = 21
10t = 21 ___ t = 2.1
RELATED QUESTIONS
Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much (answered by dabanfield,Alan3354)
Jack usually mows his lawn in 5 hours. Marilyn can mow the same yard in 4 hours. How much (answered by mananth)
Please help me
Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in (answered by ewatrrr)
Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 7 hours. How much (answered by ewatrrr)
Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 3 hours. How much (answered by checkley77)
Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 4 hours. How much (answered by solver91311)
Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 5 hours. How much (answered by stanbon,CharlesG2)
Jack usually mows his lawn in 5 hours. Marilyn can mow the same yard in 3 hours. How much (answered by josmiceli)
Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 6 hours. How... (answered by jorel1380)