SOLUTION: I need some help simplyfing this: Until now this is what i have for 2x^2 + X - 6 / 2x + 4 (2X - 3)*(x + 2) / 2(X + 2) = 2X - 3 / 2 X is not equal to 3/2

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: I need some help simplyfing this: Until now this is what i have for 2x^2 + X - 6 / 2x + 4 (2X - 3)*(x + 2) / 2(X + 2) = 2X - 3 / 2 X is not equal to 3/2       Log On

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Question 31037: I need some help simplyfing this:
Until now this is what i have for 2x^2 + X - 6 / 2x + 4
(2X - 3)*(x + 2) / 2(X + 2) = 2X - 3 / 2 X is not equal to 3/2
X is not equal to 2
Is this right?

Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify:
%282x%5E2%2Bx-6%29%2F%282x%2B4%29 Factor the numerator and the denominator, as you have done.
%28%282x-3%29%28x%2B2%29%29%2F2%28x%2B2%29 Cancel the common factors (x+2)
%282x-3%29%2F2 Which is the answer that you got!
The restrictions that you have placed on the variable x don't seem to be correct.
If you look at the original expression, you will see that only when x = -2 will the denominator become zero. So the restriction on x ought to be x cannot = -2.
Does this make sense?