SOLUTION: Factor completely
5x^2 - 6xy - 8y^2
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Question 30960This question is from textbook Introductory and Intermediate Algebra
: Factor completely
5x^2 - 6xy - 8y^2
This question is from textbook Introductory and Intermediate Algebra
Answer by ikdeep(226) (Show Source): You can put this solution on YOUR website!
5x^2 - 6xy - 8y^2
(Here you must know how we make factors i.e. splitting of the middle term...if you might not know then please contact me again and I will explain to you... )
= 5x^2 - (10-4)xy - 8y^2
= 5x^2 -10xy + 4xy - 8y^2
taking common from first two i.e. 5x^2 -10xy and last two i.e. 4xy - 8y^2
variables...we get
= 5x(x-2y) + 4y(x-2y)
= (5x + 4y)(x-2y)...........
hope this will help you
Please feel free to revert back for any further queries.
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