SOLUTION: Factor completely over the set of complex numbers
x^5-2x^4+8x^2-13+6
Algebra.Com
Question 309214: Factor completely over the set of complex numbers
x^5-2x^4+8x^2-13+6
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Should that be -13x?
RELATED QUESTIONS
Factor completely over the set of REAL numbers:... (answered by drk)
Factor x^2 +3x +6 over the set of complex... (answered by Nate)
One zero of f(x)=x^5+x^4+23x^3+23x^2−50x−50 is 5i where i=√−1. Completely factor... (answered by ikleyn)
1.Use factoring and the zero product property to solve the question.... (answered by stanbon,ewatrrr)
Solve x^3 - 4x^2 - 2x + 20 = 0 over the set of complex... (answered by Nate)
How do I factor: z^2+25, over the set of complex... (answered by venugopalramana)
how do I find all of the zeros of the polynomial f(x)=x^2-4x+13 then completely factor... (answered by ikleyn,Fombitz)
Solve over the set of complex numbers. Use completing the square.
8x^2-x-1=0 (the x... (answered by ankor@dixie-net.com)
Solve this completely over the set complex numbers (any method!):
{{{3x^2-45=6x}}}... (answered by solver91311)