SOLUTION: Factor completely 2x^2 + 16x + 32 x^3 + 3x^2 + x + 3 3x^2 + 6x - 24

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 Question 30879: Factor completely 2x^2 + 16x + 32 x^3 + 3x^2 + x + 3 3x^2 + 6x - 24Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website! You need to find a factor of this ie a value of x that makes the whole thing zero. Since all the terms are positive, then x must be a negative value, to make the and x negative. As to the value of x, well this is trial and error to find, but looking at the equation, the value -3 does jump out. Put x=-3 into the expression and you do get zero. So, x+3 is a factor. You now need to divide this into the cubic expression and then factorise the resulting quadratic, if possible. Having done this for you, the final answer is . So try it. Actually, there is a simpler method for this cubic: written as . Look the 2 sets of 2 terms and factorise each of those: You can see that both halves have , so we can factorise again, as Third example looks to be like the first. jon.