SOLUTION: { { { 7/w-5+ 6/w-3 - 3w/w^2-8w+15 } } }
i know you have to factor the denominators.
the answer i got was 13+3w.. i don't think it's right, though.
Algebra.Com
Question 30705: { { { 7/w-5+ 6/w-3 - 3w/w^2-8w+15 } } }
i know you have to factor the denominators.
the answer i got was 13+3w.. i don't think it's right, though.
Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
7/w-5+ 6/w-3 - 3w/w^2-8w+15
= 7/w-5+ 6/w-3 - 3w/(w-5)(w-3)
(factoring w^2-8w+15)
(the sum is -8 and product is 15 and hence the quantities arse -5 and -3)
=[7X(w-3)+6(w-5)-3w]/(w-5)(w-3)
=[7w-21+6w-30-3w]/(w-5)(w-3)
=[(7w+6w-3w)-21-30]/(w-5)(w-3)
=(10w-51)/(w-5)(w-3)
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