SOLUTION: How do I factor each of these polynomials completely. x^3+x^2-x-1 and 3a-3b-xa+ax I know I have to group the factors. After that I get lost.

Question 305410: How do I factor each of these polynomials completely.
x^3+x^2-x-1 and 3a-3b-xa+ax
I know I have to group the factors. After that I get lost.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
x^3+x^2-x-1
=x^2(x+1)-(x+1)
=(x^2-1)(x+1)
.
3a-3b-xa+ax
=3(a-b) because -xa+ax=-ax+ax=0
.
Ed
RELATED QUESTIONS
how do i solve... (answered by jim_thompson5910)

I have a question about the remaining factors. If you have an equation of x^3+5x^2=2x-8... (answered by richwmiller,stanbon)

Factor as completely as possible. a) {{{x^3-4x}}} b) {{{xy-x+8y-8}}} c)... (answered by Mathematicians,JBarnum)

a^2-b^2 x ab^2 _______ _____ a^4 b 3a+3b I'm not quite sure how to solve... (answered by Alan3354)

Hi. I'm teaching myself Algebra for the GRE because I somehow missed all the math in... (answered by ewatrrr)

How do I multiply the factors and combine these like terms... (answered by london maths tutor)

12a^2+36a+27 x^3+x^2-x-1 3a-3b-xa+xb If you can please help me with these... (answered by dabanfield)

I need to factor x^2+8x+16 So far i have (x ) (x ) I know the factors of... (answered by Edwin McCravy)

How will I go about simplifing these problem? 1) 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)] (answered by edjones)