SOLUTION: Need help with trinomials! Any guidance on this set would be GREATLY appreciated!!
3. a) Factor completely.
v^3-5v^2-36v
b)Solve and simplify:
r^2+3r-18=0
c)Solve
Algebra.Com
Question 303320: Need help with trinomials! Any guidance on this set would be GREATLY appreciated!!
3. a) Factor completely.
v^3-5v^2-36v
b)Solve and simplify:
r^2+3r-18=0
c)Solve for the solution set.
(x+9)(x-13)(x+6)>0
d)Factor completely:
c^2+4c+4
e)Factor completely in factored form:
3x^7-15x^6+24x^5
f)Multiply
(-3n)^2 * (4n^9)^2
Thank you so much for your help!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started. Please only post one problem at a time.
a)
Start with the given expression.
Factor out the GCF .
Now let's try to factor the inner expression
---------------------------------------------------------------
Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .
Now multiply the first coefficient by the last term to get .
Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?
To find these two numbers, we need to list all of the factors of (the previous product).
Factors of :
1,2,3,4,6,9,12,18,36
-1,-2,-3,-4,-6,-9,-12,-18,-36
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to .
1*(-36) = -36
2*(-18) = -36
3*(-12) = -36
4*(-9) = -36
6*(-6) = -36
(-1)*(36) = -36
(-2)*(18) = -36
(-3)*(12) = -36
(-4)*(9) = -36
(-6)*(6) = -36
Now let's add up each pair of factors to see if one pair adds to the middle coefficient :
First Number | Second Number | Sum | 1 | -36 | 1+(-36)=-35 |
2 | -18 | 2+(-18)=-16 |
3 | -12 | 3+(-12)=-9 |
4 | -9 | 4+(-9)=-5 |
6 | -6 | 6+(-6)=0 |
-1 | 36 | -1+36=35 |
-2 | 18 | -2+18=16 |
-3 | 12 | -3+12=9 |
-4 | 9 | -4+9=5 |
-6 | 6 | -6+6=0 |
From the table, we can see that the two numbers and add to (the middle coefficient).
So the two numbers and both multiply to and add to
Now replace the middle term with . Remember, and add to . So this shows us that .
Replace the second term with .
Group the terms into two pairs.
Factor out the GCF from the first group.
Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
Combine like terms. Or factor out the common term
--------------------------------------------------
So then factors further to
===============================================================
Answer:
So completely factors to .
In other words, .
Note: you can check the answer by expanding to get or by graphing the original expression and the answer (the two graphs should be identical).
===========================================================================
b)
Start with the given equation
Factor the left side
Now set each factor equal to zero:
or
or Now solve for r in each case
So the solutions are or
RELATED QUESTIONS
A) Factor each polynomial completely, given that the binomial following it is a factor of (answered by stanbon)
Solve the inequality
55. -7/11d + 2 < 2/3
Any help with this equation would be... (answered by josmiceli)
Solve the inequality
55. -7/11d + 2 < 2/3
Any help with this equation would be... (answered by jim_thompson5910)
Solve the equation
46. 3/4w = -1/2
Any help with this equation would be... (answered by stanbon)
Solve the inequality
54.2/5k - 4/15 > -2/3
Any help with this equation would be... (answered by jim_thompson5910)
Solve the equation.
46. 3/4w = -1/2
Any help with this equation would be... (answered by HyperBrain)
Show that the numbers is rational by writing it as a quotient of two intergers.
2. 3
(answered by HyperBrain)
I need help with this problem:
3^log base 3 of 8
Any help would be greatly... (answered by josgarithmetic,josmiceli)
Hi
I am stuck on this one which has me completely bamboozled. Your assistance would be... (answered by solver91311,stanbon)