SOLUTION: I have no idea where to even begin. Please help. Divide using synthetic division. (2x^3 - 14x^2 + 19x + 20) / (x

SOLUTION: I have no idea where to even begin. Please help. Divide using synthetic division. (2x^3 - 14x^2 + 19x + 20) / (x - 4)

Question 30074: I have no idea where to even begin. Please help.
Divide using synthetic division.
(2x^3 - 14x^2 + 19x + 20) / (x - 4)
Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
Divide using synthetic division.
(2x^3 - 14x^2 + 19x + 20) / (x - 4)
That is to use the synthetic division to find f(4) if f(x) =2x^3-14x^2+19x+20.
---- 2 -14 19 20
(4)| 8 -24 -20
-------------------------------------
---- 2 -6 -5 0
We observe that the remainder is 0 and the quotient is given by
2x^2-6x-5
The working procedure is as follows
Note: Leave out the x's and write down the numbers (called coefficients) of the first polynomial on the first line. Then put (4) (which comes from (x-4) on the second line.
Start by copying the first 2 onto the bottom line. Multiply by 4 to get the 8 and write in the second line underneath -14. Add the top -14 to this 8 to
get -6. Keep repeating this by multiplying each number on the bottom line by
4, and add the result to the top line, with the result of the addition going on the bottom line.
The last number is the remainder
Look at the bottom line and write down the quotient polynomial
(2x^3 - 14x^2 + 19x + 20) / (x - 4)
= 2x^2-6x-5

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