SOLUTION: Solve by the LCM method:
{{{6/(y+3)+ 2/y =(5y-3)/(y^2-9)}}}
I am unable to come up with the LCD: (y+3)(y-3)? Unsure of how to work this. Once I have the LCD, I believe I wi
Algebra.Com
Question 299158: Solve by the LCM method:
I am unable to come up with the LCD: (y+3)(y-3)? Unsure of how to work this. Once I have the LCD, I believe I will be able to solve it. Thank you in advance for your help.
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
6 / y+3 -5y-3 / y^2-9= 2/y
6(y-3) - (5y-3) / y^2-9 = 2/y
6y-18 -5y+15 = 2(y^2-9) /y
y-3= 2(y^2-9) /y
y(y-3)= 2 (y^2-9)
y= 2(y+3)(y-3) / (y-3)
y=2(y+3)
y=2y+6
y=-6
Ananth
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Solve by the LCM method:
-------- Multiply by LCD,
(y - 6)(y + 1) = 0
or
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