SOLUTION: what are the steps to factoring this problem 3(x)2+8x+5

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Question 297405: what are the steps to factoring this problem 3(x)2+8x+5
Answer by richwmiller(9135) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2+8x+5
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)
In order to factor 3%2Ax%5E2%2B8%2Ax%2B5, first multiply the leading coefficient 3 and the last term 5 to get 15. Now we need to ask ourselves: What two numbers multiply to 15 and add to 8? Lets find out by listing all of the possible factors of 15


Factors:

1,3,5,15,

-1,-3,-5,-15, List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to 15.

1*15=15

3*5=15

(-1)*(-15)=15

(-3)*(-5)=15

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to 8? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 8

||||
First Number|Second Number|Sum
1|15|1+15=16
3|5|3+5=8
-1|-15|-1+(-15)=-16
-3|-5|-3+(-5)=-8


We can see from the table that 3 and 5 add to 8. So the two numbers that multiply to 15 and add to 8 are: 3 and 5

So the original quadratic


3%2Ax%5E2%2B8%2Ax%2B5


breaks down to this (just replace 8%2Ax with the two numbers that multiply to 15 and add to 8, which are: 3 and 5)


3%2Ax%5E2%2Bhighlight%283x%2B5x%29%2B5 Replace 8%2Ax with 3x%2B5x

Group the first two terms together and the last two terms together like this:

%283%2Ax%5E2%2B3x%29%2B%285x%2B5%29

Factor a 3x out of the first group and factor a 5 out of the second group.


3x%28x%2B1%29%2B5%28x%2B1%29


Now since we have a common term x%2B1 we can combine the two terms.


%283x%2B5%29%28x%2B1%29 Combine like terms.
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Answer:


So the quadratic 3%2Ax%5E2%2B8%2Ax%2B5 factors to %283x%2B5%29%28x%2B1%29




Notice how %283x%2B5%29%28x%2B1%29 foils back to our original problem 3%2Ax%5E2%2B8%2Ax%2B5. This verifies our answer.