SOLUTION: subtracting rational expressions having different denominators I have a solution to this problem but I need to know if it is correct. 7x^2+15x- 11(numerator )over2x^2-5x+2

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: subtracting rational expressions having different denominators I have a solution to this problem but I need to know if it is correct. 7x^2+15x- 11(numerator )over2x^2-5x+2      Log On

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 Question 295775: subtracting rational expressions having different denominators I have a solution to this problem but I need to know if it is correct. 7x^2+15x- 11(numerator )over2x^2-5x+2(denominator) subtracted from -4x+5 (numerator)over x-2(denomintor )Found 2 solutions by richwmiller, stanbon:Answer by richwmiller(9143)   (Show Source): You can put this solution on YOUR website! Is this what you want? What is your solution? (2x^2-5x+2) factors to (x-2)*(2x-1) or did you want this? Answer by stanbon(57410)   (Show Source): You can put this solution on YOUR website!7x^2+15x- 11(numerator )over2x^2-5x+2(denominator) subtracted from -4x+5 (numerator)over x-2(denomintor ) ----------------- [7x^2+15x-11] / [2x^2-5x+2] - [-4x+5] / [x-2] ---------------------------------- Factor the denominator of the 1st fraction: 2x^2-5x+2 2x^2 -4x-x +2 2x(x-2)-(x-2) (x-2)(2x-1) ---------------- So the least common denominator is (x-2)(2x-1) ------------------- Rewrite each fraction with the lcd as its denominator: [7x^2+15x-11]/lcd - [2x-1][-4x+5]/lcd ----- Combine the numerators over the lcd: [7x^2+15x-11-[-7x^2+10x+4x-5]]/lcd ------------------------------------- Simplify: [14x^2+29x-5]/[2x^2-5x+2] ================================ Cheers, Stan H. =================================