SOLUTION: x^2 - 3x - 28 ---------------- x^2 - 9x + 14 Assume that the denominator is not equal to zero.

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Question 292068: x^2 - 3x - 28
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x^2 - 9x + 14 Assume that the denominator is not equal to zero.
Answer by richwmiller(9144) About Me  (Show Source):
You can put this solution on YOUR website!
Try to find factors for both num. and den. and cancel out the same.
(x-7)*(x+4)=x^2-3x-28
(x-7)*(x-2)=x^2-9x+14
so we end up with
(x+4)/(x-2)