SOLUTION: The Question is c^3+16cd+48cd I looked at 16cd and I figured what you had to add to get 16 (c+14cd) (c+2cd) In the back of the book it stated (c+12cd) (c+4cd) Here is the

Question 290992: The Question is c^3+16cd+48cd
I looked at 16cd and I figured what you had to add to get 16
(c+14cd) (c+2cd)
In the back of the book it stated (c+12cd) (c+4cd)
Here is the example from the textbook to give a more clear explaination
x^2-10xy+21y^2
X^2-10xy+21y^2=(x-3y)(x-7y)
MY question is how can my answers be correct . Why would the text book answer say that 12 and 4 is the answer. I know that is another sum of 16 .
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Do you know how to FOIL?
FOIL your answer back to the original.
Neither of your answers are correct, I promise that you copied several things wrong.

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