SOLUTION: How would I solve the equation 2x^2-3x-35=0? PLEASE HELP!!

SOLUTION: How would I solve the equation 2x^2-3x-35=0? PLEASE HELP!!

Algebra.Com

Question 290739: How would I solve the equation 2x^2-3x-35=0?
PLEASE HELP!!
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
2x^2-3x-35=0
Factoring, we get:
2x^2 -10x +7x -35 =0
(2x^2 -10x) + (7x -35) =0
2x(x-5) + 7(x-5) =0
(x-5)(2x+7) = 0
x = {-7/2, 5}
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