SOLUTION: if x^2 + y^2 =36 and (x+y)^2 =64 what is the value of xy
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Question 290730: if x^2 + y^2 =36 and (x+y)^2 =64 what is the value of xy
Answer by gsmani_iyer(201) (Show Source): You can put this solution on YOUR website!
Remember an identity .. With this identity, we can solve the problem.
= or . whereas ok?
But ; in the above identity, we dont have the value of 2xy.
So, which is = 28. Therefore, 2xy = 28.
So, xy = 28/2 = 14. Answer. Therefore the value of xy = 14. I hope this is clear to you. Best of luck. Feel free to contact me anytime online on any doubts in mathematics.
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