SOLUTION: Problem is:
{{{(8)/(2m+1)-(1)/(m-2)=(5)/(2m+1)}}}
I've tried several ways, but can't come up with an answer that fits in the slot for "m". Is this unsolvable?
My most current a
Algebra.Com
Question 288344: Problem is:
I've tried several ways, but can't come up with an answer that fits in the slot for "m". Is this unsolvable?
My most current attempt at a solution:
by adding to the left side and subtracting from the left and adding it to the right side.
This equals
I then tried multiplying each side by (m-2) which brought me to
and broken down even further, this comes to
which breaks down to
and with left to fend for himself.
all that makes
so I added the -8 to each side and got
Now I'm not sure what to do (if I've even been doing it right so far)
Do I divide each side by 2 to break up the or am I already too far gone?
I could try moving the 9 back over to the left side and trying a quadratic formula, but these numbers just don't look right together. The last three problems were unsolvable, which leaves me questioning whether or not this one is, too, and if not, was I wrong on all of the other ones??
Any suggestions on what I should change or how to fix whatever I'm doing wrong?
Any help is appreciated, thank you!
Found 2 solutions by Alan3354, richwmiller:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Problem is:
-------------------
Multiply thru by (2m+1)*(m-2)
8(m-2) - (2m+1) = 5(m-2)
8m-16 - 2m-1 = 5m-10
6m - 17 = 5m-10
m = 7
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
m=7
Where did you go wrong??
(3)/(2m+1)=(1)/(m-2) is good.
(3m-6)+(2m+1)(m-2)=1 this is bad
(3)/(2m+1)=(1)/(m-2) should be
3(m-2)=2m+1
3m-6=2m+1
subtract 2m from both sides
m-6=1
m=7
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