SOLUTION: The Boxerville city council must pay three companies to have street lamps put on the 4th Street Bridge. Company M will make the lamps for $25 per lamp, plus $125 fee. Company S wi

Question 288243: The Boxerville city council must pay three companies to have street lamps put on the 4th Street Bridge. Company M will make the lamps for $25 per lamp, plus $125 fee. Company S will install the lamps for $40 per lamp, plus $100 fee. Company P will paintthe lamps for $15 per lamp, plus a $50 fee.
Using n as the number of lamps, write a polynomial for each company that tells you how much the company will charge.
Company M? = 25n + 125?
Company S? = 40n + 100?
Company P? = 15n + 50?
find the sum of the three polynomials? = 80n + 275?
Use the sum you found to write an inequality that shows that the city council can pay no more than $3,500 total. 80n - 3225
How many street lamps can they put on the bridge for $3,500?
How many lamps can they put on the bridge for 4,300?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The Boxerville city council must pay three companies to have street lamps put on the 4th Street Bridge. Company M will make the lamps for $25 per lamp, plus $125 fee. Company S will install the lamps for $40 per lamp, plus $100 fee. Company P will paintthe lamps for $15 per lamp, plus a $50 fee.
---------------------------------
Using n as the number of lamps, write a polynomial for each company that tells you how much the company will charge.
Company M? = 25n + 125?
Company S? = 40n + 100?
Company P? = 15n + 50?
find the sum of the three polynomials? = 80n + 275?
Use the sum you found to write an inequality that shows that the city council can pay no more than $3,500 total. 80n + 275 <= 3500
-------
How many street lamps can they put on the bridge for $3,500?
Solve: 80n+275 <= 3500
80n <= 3225
n <= 40.31
Round down to get n = 40
-------------------------------
How many lamps can they put on the bridge for 4,300?
80n+275 <= 4300
80n <= 4025
n <= 50.31
Round down to get n = 50
==============================
Cheers,
Stan H.

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