SOLUTION: Hi, I need help with solving the following equation. I can get half way through it and get stuck. Here goes... 2x over x+2-2= x-8 over x-2. I'm stuck at 2x (x-2)-2(x+2), over wha

Question 285198: Hi, I need help with solving the following equation. I can get half way through it and get stuck. Here goes... 2x over x+2-2= x-8 over x-2. I'm stuck at 2x (x-2)-2(x+2), over what? is it over (x-2) (x+2)?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
2x/(x+2)-2=(x-8)/(x-2)
2x-2x-4)/(x+2)=(x-8)/(x-2)
-4/(x+2)=(x-8)/(x-2)
-4(x-2)=(x-8)*(x+2)
-4x+8=x^2-16x+2x-16
0=x^2-8x+2x+4x-8-16
0=x^2-2x-24

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=100 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6, -4. Here's your graph:

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