SOLUTION: the product of two consecutive positive odd integers is one less than three times their sum. find the integers.

Question 283300: the product of two consecutive positive odd integers is one less than three times their sum. find the integers.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the number be x
the second number will be x+2
the product will be x(x+2)
three times the sum less 1 = 3(x+x+2)-1
x(x+2)=3(2x+2)-1
x^2+2x=6x+6-1
x^2+2x-6x=+6-1
x^2-4x=+5
x^2-4x-5=0
x^2-5x+x-5=0
x(x-5)+1(x-5)=0
(x+1)(x-5)=0
x=-1 or 5
So 5 & 7 are the numbers
RELATED QUESTIONS
The product of two consecutive positive odd integers is one less than three times their... (answered by Deina)

The product of two positive consecutive odd integers is 1 less than 5 times their sum.... (answered by KMST)

The product of two consecutive positive odd integers is one less than twice their sum.... (answered by Fombitz)

product of two consecutive, odd, positive, integers is one less than 5 times their... (answered by solver91311)

Solve using the five-step problem-solving process. Show all steps necessary to arrive at... (answered by helpnalgebra)

The product of two consecutive positive odd integers is one less than three times their... (answered by scott8148,checkley77)

The product of two consecutive odd integers is 1 less than four times their sum. Find... (answered by RAY100)

The product of two consecutive odd integers is 1 less than four times their sum. Find... (answered by drj)

The product of two consecutive odd integers is 57 less than 9 times their sum. Find the... (answered by CubeyThePenguin,josgarithmetic)