SOLUTION: how do I evaluate polynomials 2x^2y-xz^3 for x = -3 y=1 and z= 3 Please explain Thanks

Algebra.Com
Question 281098: how do I evaluate polynomials
2x^2y-xz^3 for x = -3 y=1 and z= 3
Please explain
Thanks

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
for every x in the expression put -3
for every y put 1
for every z put 3
2*(-3)^2*1-3*(3^3)
remember order of operations
pemdas
parentheses first
then exponents

RELATED QUESTIONS

Hello, I'm reviewing for a final and need some help checking this problem: Evaluate... (answered by Edwin McCravy)
evaluate polynomial 2x^2y -xz^3 for x= -3 y= 1 z= 3 2(-3)^2(1)-(-3)(3)^3... (answered by vleith)
evaluate the expression for: x=3,y=2,z=5... (answered by ewatrrr)
how do i do this?evaluate 3x^2y+2xy+5y for x=3 and y=2 thanks so... (answered by adamchapman)
evalute the expression for: x=3, y=2, z=5:... (answered by ewatrrr)
If (x^2)(y^3)(z^5) is positive, which product is always positive? A) xz B) (y^2)z C) (answered by richard1234)
Hi! I need help solving (x^-2y^-2/xz)/(xy/y^-2z^3) thanks in advance for your... (answered by tanimachatterjee)
How do I evaluate x=-3,y=7, and... (answered by Fombitz,Shin123)
If (x^2)(y^3)z < 0, which of the following statements must be true? I. yz < 0 II. xz... (answered by richard1234)