SOLUTION: Divide 28x^3-23x^2-47x-18/7x+3 Simplify answer

Algebra.Com
Question 280569: Divide
28x^3-23x^2-47x-18/7x+3
Simplify answer

Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
(In the future, please put parentheses aroung multi-term numerators and denominators. Tutors are more likely to respond to a problem that is clearly stated.)

       4x^2  -5x    -32/7
      ____________________________
7x+3 /28x^3  -23x^2  -47x  -18
      28x^3  +12x^2
      -------------
             -35x^2  -47x
             -35x^2  -15x
             ------------
                     -32x  -18
                     -32x  -96/7
                     -----------
                           -30/7

So
The remainder fraction will simplify:


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